传热学综合传热.ppt

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1、Chapter Twelve,Multimode Heat And Mass Transfer,That most technically important problems involve multimode heat transfer effects.,To solve such problems,it may be necessary to simultaneously work with heat equation,surface energy balance,overall energy balances,and approprite rate rate equations for

2、 conduction,convection and radiation heat transfer.,Example 12.1The rear window of an automobile is of thickness L=8mm and height H=0.5m and contains fine-meshed heating wires that can induce nearly volumetric heating.Consider steady-state conditions for which the interior surface of the window is e

3、xposed to air at 10,while the exterior surface is exposed to air at-10 and a very cold sky with an effective temperature of-33.The air moves in parallel flow over the surface with a velocity of 20m/s.Determine the volumetric heating rate needed maintain the interior window surface at Ts,i=15.solutio

4、nKnown:Boundary conditions associated with a rear window experiencing uniform volumetric heating.Find:Volumetric heating rate needed to maintain inner surface temperature at Ts,i=15.Schematic:,Assumptions:steady-state,one-dimensional conditions.Constant properties.Uniform volumetric heating in windo

5、w.Convection heat transfer from interior surface of window to interior air may be approximated as free convection from a vertical plate.Radiation exchange with automobile interior is negligible.Heat transfer from outer surface is due to forced convection over a flat plate and radiation exchange with

6、 the sky.Boundary layer separation on the outer surface in negligible.Outer surface is diffuse and gray.Properties:Glass;Air;k,v,Pr,(look at tables),Analysis:The temperature distribution in the glass is governed by the appropriate form of the heat equation.,Boundary conditions,Applying an energy bal

7、ance to the inner surface,Hence,Applying an energy balance to the outer surface.,(1),(2),(3),The inside convection coefficient may be obtained from Equation,The outside convection coefficient may be obtained by first evaluating the Reynolds number.,Mixed boundary layer conditions,(4),(5),Equation 5

8、may be expressed as,(6),Substituting into equation 4,Example 12.2 The composite insulation shown is being considered as a roofing material.,Known:Dimensions of a composite insulation consisting of a honeycomb core sandwiched between solid slabs.Find:Total thermal resistance.Schematic:because is no l

9、ateral heat from cell to cell,and it suffices to consider the heat transfer across a single cell.,Assumptions:1.One-dimensional,steady-state conditions.2.Equivalent conditions for each cell.3.Constant properties.4.Diffuse,gray surface behavior.Properties:,Analysis:The total resistance of the composi

10、te is determined by conduction,convection and radiation processes occurring within the honeycomb and by conduction across the inner and outer slabs.The corresponding thermal circuit is shown.,The total resistance of the composite is,The equivalent resistance for the honecomb is,The cell forms an enc

11、losure that may be classified as a horizontal cavity heated from below,and the appropriate form of the Rayleigh number is,The resistance to heat transfer by radiation may be obtained by first noting that the cell forms a three-surface enclosure for which the sidewalls are reradiating.,Example 12.3 C

12、ylindrical dry-bulb thermometer is installed in a large diameter duct to obtain the temperature T air flowing through the duct at a velocity V.the duct inside surface is at known temperature Ts which less then T.,Known:Dry-bulb temperature associated with air flow through a large diameter duct of pr

13、escribed surface temperature.Find:Temperature of airflow.Schematic:,Dry-bulb thermometer,Assumption:Steady-state conditions exit.Heat transfer by conduction along the thermometers is negligible.Duct wall forms a large enclosure about the thermometer.Thermometer surface are diffuse gray.Properties:(a

14、ir)v,k,Pr.,Analysis:Since TdbTs,there is net radiation transfer from the surface of the dry-bulb thermometer to the duct wall.Hence to maintain steady-state conditions,the thermometer temperature must be less than that of the air to allow for convection heat transfer from the air.From application of a surface energy balance to the thermometer,The air temperature is then,(1),For the prescribed conditions the Reynolds number associated with the dry-bulb thermometer is,Comments:The effect of radiation exchange between the duct wall and the thermometer is small.For this reason.,