Digital_Transmission_Fundamentals.ppt
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1、1,Chapter 4 Digital Transmission Fundamentals,4.1 Digital Representation of Information4.2 Why Digital Communications?4.3 Digital Representation of Analog Signals4.4 Characterization of Communication Channels4.5 Fundamental Limits in Digital Transmission4.6 Line Coding4.7 Modems and Digital Modulati
2、on4.8 Properties of Media and Digital Transmission Systems4.9 Error Detection and Correction,2,The Seven-Layer OSI Reference Model,ApplicationLayer,PresentationLayer,SessionLayer,TransportLayer,NetworkLayer,Data LinkLayer,PhysicalLayer,ApplicationLayer,PresentationLayer,SessionLayer,TransportLayer,N
3、etworkLayer,Data LinkLayer,PhysicalLayer,NetworkLayer,Application,Application,Data LinkLayer,PhysicalLayer,NetworkLayer,Data LinkLayer,PhysicalLayer,Communicating End Systems,One or More Network Nodes,End-to-End Protocols,3,Physical Layer,Transfers bits across linkDefinition&specification of the phy
4、sical aspects of a communications linkEthernet,DSL,cable modem,telephone modemsTwisted-pair cable,coaxial cable optical fiber,radio,infrared,4,Chapter 4 Digital Transmission Fundamentals,Digital Representation of Information,5,Block vs.Stream Information,BlockInformation that occurs in a single bloc
5、kSize=Bits/blockor bytes/block1 kbyte=210 bytes1 Mbyte=220 bytes1 Gbyte=230 bytes,StreamInformation that is produced&transmitted continuouslyBit rate=bits/second1 kbps=103 bps1 Mbps=106 bps1 Gbps=109 bps,6,Digitization of Analog Signal,Sample analog signal in time and amplitudeFind closest approxima
6、tion,Original signal,Sample value,Approximation,Rs=Bit rate=#bits/sample x#samples/second,3 bits/sample,7,Bit Rate of Digitized Signal,Bandwidth Ws Hertz:Higher bandwidth more frequent samplesMinimum sampling rate=2 x WsRepresentation accuracy:range of approximation errorHigher accuracy smaller spac
7、ing between approximation values more bits per sample,8,Example:Voice&Audio,Telephone voiceWs=4 kHz 8000 samples/sec8 bits/sampleRs=8 x 8000=64 kbpsCellular phones use more powerful compression algorithms:8-12 kbps,CD AudioWs=22 kHertz 44000 samples/sec16 bits/sampleRs=16 x 44000=704 kbps per audio
8、channelMP3 uses more powerful compression algorithms:50 kbps per audio channel,9,Chapter 4 Communication Networks and Services,Why Digital Communications?,10,A Transmission System,Transmitter:Converts information into signal suitable for transmissionInjects energy into communications medium or chann
9、elReceiver:Receives energy from mediumConverts received signal into form suitable for delivery to user,11,Transmission Impairments,Communication ChannelPair of copper wiresCoaxial cableRadio Light in optical fiberLight in airInfrared,Transmission ImpairmentsSignal attenuationSignal distortionSpuriou
10、s noiseInterference from other signals,12,Analog Long-Distance Communications,Each repeater attempts to restore analog signal to its original formRestoration is imperfectDistortion is not completely eliminatedNoise&interference is only partially removedSignal quality decreases with#of repeatersCommu
11、nications is distance-limited,13,Analog vs.Digital Transmission,Analog transmission:all details must be reproduced accurately,Sent,Received,Received,DistortionAttenuation,Digital transmission:only discrete levels need to be reproduced,DistortionAttenuation,Simple Receiver:Was original pulse positive
12、 or negative?,14,Digital Long-Distance Communications,Regenerator recovers original data sequence and retransmits on next segmentCan design so error probability is very smallThen each regeneration is like the first time!Communications is possible over very long distancesDigital systems vs.analog sys
13、temsLess power,longer distances,lower system costMonitoring,multiplexing,coding,encryption,protocols,15,Digital Binary Signal,For a given communications medium:How do we increase transmission speed?How do we achieve reliable communications?Are there limits to speed and reliability?,Bit rate=1 bit/T
14、seconds,16,Pulse Transmission Rate,Objective:Maximize pulse rate through a channel,that is,make T as small as possible,Channel,t,t,pulse frequently without interfering with each other:2 x Wc pulses/second for lowpass channel Wc pulses/second for bandpass channelWc is the bandwidth of the channel,T,1
15、7,Multilevel Pulse Transmission,If pulses amplitudes are either-A or+A,then each pulse conveys 1 bit,so Bit Rate=1 bit/pulse x 2Wc pulses/sec=2Wc bpsIf amplitudes are from-A,-A/3,+A/3,+A,then bit rate is 2 x 2Wc bpsBy going to M=2m amplitude levels,we achieve Bit Rate=m bits/pulse x 2Wc pulses/sec=2
16、mWc bps,18,Noise&Reliable Communications,All physical systems have noisePresence of noise limits accuracy of measurement of received signal amplitudeErrors occur if signal separation is comparable to noise levelBit Error Rate(BER)increases with decreasing signal-to-noise ratioNoise places a limit on
17、 how many amplitude levels can be used in pulse transmission,19,SNR=,Average signal power,Average noise power,SNR(dB)=10 log10 SNR,Signal-to-Noise Ratio,error,No errors,20,Arbitrarily reliable communications is possible if the transmission rate R C,then arbitrarily reliable communications is not pos
18、sible.“Arbitrarily reliable”means the BER can be made arbitrarily small through sufficiently complex coding.C can be used as a measure of how close a system design is to the best achievable performance.,Shannon Channel Capacity,C=Wc log2(1+SNR)bps,21,Example,Find the Shannon channel capacity for a t
19、elephone channel with Wc=3400 Hz and SNR=10000 C=3400 log2(1+10000)=3400 log10(10001)/log102=45200 bpsNote that SNR=10000 corresponds to SNR(dB)=10 log10(10001)=40 dB,22,Bit Rates of Digital Transmission Systems,23,Examples of Channels,24,Chapter 4 Digital Transmission Fundamentals,Digital Represent
20、ation of Analog Signals,25,Interpolationfilter,(a),(b),Nyquist:Perfect reconstruction if sampling rate 1/T 2Ws,Sampling Theorem,26,Digital Transmission of Analog Information,27,Quantization error:“noise”=x(nT)y(nT),Quantizer maps inputinto closest of 2mrepresentation values,Quantization of Analog Sa
21、mples,28,W=4KHz,so Nyquist sampling theorem 2W=8000 samples/second8 bits/samplePCM(“Pulse Code Modulation”)Telephone Speech:Bit rate=8000 x 8 bits/sec=64 kbps,Example:Telephone Speech,29,Chapter 4 Digital Transmission Fundamentals,Characterization of Communication Channels,30,Communications Channel,
22、Signal Bandwidthtransfer data faster,a signal varies more quickly.Channel BandwidthA channel or medium has an inherent limit on how fast the signals it passes can vary,Transmission ImpairmentsSignal attenuationSignal distortionSpurious noiseInterference from other signals,Transmitted Signal,Received
23、 Signal,Receiver,Communication channel,Transmitter,31,Ideal Low-Pass Filter,Ideal filter:all sinusoids with frequency fWc are passed without attenuation and delayed by t seconds;sinusoids at other frequencies are blocked,Amplitude Response,Wc,y(t)=Aincos(2ft-2ft)=Aincos(2f(t-t)=x(t-t),32,Example:Low
24、-Pass Filter,Simplest non-ideal circuit that provides low-pass filtering,33,Bandpass Channel,Some channels pass signals within a band that excludes low frequenciesTelephone modems,radio systems,Channel bandwidth is the width of the frequency band that passes non-negligible signal power,34,Chapter 4
25、Digital Transmission Fundamentals,Fundamental Limits in Digital Transmission,35,Noise distribution,Noise is characterized by probability density of amplitude samplesNoise distribution is Gaussian(bell-shaped)as below,t,PrX(t)x0=?,PrX(t)x0=Area undergraph,x0,x0,s2=Avg Noise Power,36,Probability of Er
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