C语言程序设计基础实验与题解 答案(最新修改版).doc
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1、 C语言程序设计基础实验与题解实验一 (1)定义iNUM时未对其初始化,修改程序参考如下: #includevoid main(void)int iNUM=5;float fNUM=134.23;printf(a=%dtf=%.2fn,iNUM,fNUM);运行结果:a=5 f=134.23Press any key to continue_(2)#includevoid main()int a,b,c,sum=0;scanf(a=%d,%d%d,&a,&b,&c);sum=a+b+c;printf(a=%d,b=%d,c=%dn,a,b,c);printf(sum=%d,sum);输入及其运
2、行结果:a=4,6 7a=4,b=6,c=7sum=17Press any key to continue_(3)#includevoid main()char a,b;scanf(%3c%4c,&a,&b);printf(C1=%c,C2=%c,a+1,b-1);运行结果:ABCDEFGHC1=B,C2=CPress any key to continue_(4)#include#includevoid main()float a;printf(Enter a: );scanf(%f,a);printf(The original data is:%fnn,a);printf(The tran
3、sformed data is:%.2fn);(5)#includevoid main()int a,b,c,d,f;printf(请输入两个整数:);scanf(%d%d,&a,&b);c=a+b;d=c*c;f=a*a+b*b;printf(它们的和为:%dn,c);printf(和的平方为:%dn,d);printf(平方的和为:%dn,f);(6)#includevoid main()float a,b;printf(输入华氏温度值:);scanf(%f,&a);b=(a-32)*5/9;printf(%f()=%.2f()n,a,b);(7)#includevoid main()fl
4、oat a,b,c;printf(请输入该球队赢球场数和输球场数:);scanf(%f%f,&a,&b);c=a/(a+b);c=c*100;printf(该队赢球百分比:%.2fn,c);实验二(1)#includevoid main()float x,y;printf(请输入x的值:);scanf(%f,&x);if(x1&x10)y=2*x-1;elsey=3*x-11;printf(按公式计算得y的值为:%fn,y);(2)#includevoid main()int i,j=0,k=0;char a50;printf(请输入若干字符:);gets(a);for(i=0;ai!=0;i
5、+)if(48=ai&ai=57)j+;if(65=ai&ai=90)|(97=ai&ai=122)k+;printf(数字字符的个数为:%dn,j);printf(英文字母的个数为:%dn,k);(3)#include#includevoid main() float a,b,c,d,e,f,x1,x2;printf(求解ax2+bx+c=0的根,请输入a,b,c的值:);scanf(%f%f%f,&a,&b,&c);if(a=0&b=0&c=0) printf(此方程有任意实数解。); if(a=0&b=0&c!=0) printf(此方程无实数解。);if(a!=0)d=b*b-4*a*
6、c;if(d0)f= sqrt( d);f=f/(2*a);e=-b/(2*a);x1=e+f;x2=e-f;printf(此方程有两不等实根:x1=%f,x2=%f,x1,x2);printf(n);(4)#includevoid main()float p,t;printf(请输入该公司员工该月所接工程的利润:);scanf(%f,&p);if(p1000&p2000&p5000&p10000)t=0.25*p;printf(该员工的利润提成为%.2fn,t);(5)#includevoid main()int a,b,c,t;printf(请输入三个整数:);scanf(%d%d%d,&
7、a,&b,&c);if(ab)t=a;a=b;b=t;if(bc)t=a;a=b;b=t; if(ab)t=b;b=c;c=t;printf(居中的数为:%dn,b);实验三1.#includevoid main()int a,b;printf(在2-1000之间的守形数如下:n);for(a=2;a=1000;a+)b=a*a;if(b%10=a|b%100=a|b%1000=a|b%10000=a)printf(%d ,a);printf(n);2.#includevoid main ()int m,n,i,min,t;printf(请输入两个正整数:);scanf(%d%d,&m,&n)
8、;if(m=0|n=0)printf(输入错误!);elsemin=mn?m:n;i=2;while(i=min)if(m%i=0&n%i=0)t=i;i+;printf(%d和%d的最大公约数是%d,最小公倍数是%d.n,m,n,t,(m*n)/t);3.#includevoid main()int a,n,s,i,t;printf(输入a和n的值:);scanf(%d%d,&a,&n);printf(a=%d,n=%d.n,a,n);t=a;for(i=1,s=0;i=n;i+)s=s+t;t=t*10+a;printf(a+aa+aaa+aa.a=%dn,s);4.#includevoi
9、d main()int n,s=0;printf(输入一个正整数:);scanf(%d,&n);dos+=n%10;n/=10;while(n0);printf(各位数之和是:%dn,s);5.#includevoid main()int i,x,y=1;for(i=1;i10;i+)x=2*(y+1);y=x;printf(第一天共摘下桃子数为:%dn,x);实验四1.#includevoid main()int i,j,s=1;for(i=1;i=1000;i+)s=1;for(j=2;j=i/2;j+)if(i%j=0)s+=j;if(s=i)printf(%d=1,i);for(j=2
10、;j=i/2;j+)if(i%j=0)printf(+%d,j);printf(n);2.#includevoid main()int i,a,b,c;for(a=6;a=10000;a+)b=c=1;for(i=2;i=a/2;i+)if(a%i=0)b=b+i;for(i=2;i=b/2;i+)if(b%i=0)c=c+i;if(a=c&a!=b)printf(%6d,%6dn,a,b);运行结果: 220, 284 284, 220 1184,1210 1210,1184 2620,2924 2924, 2620 5021,5564 5564, 5020 6232,6368 6368,
11、6232Press any key to continue_3.#includevoid main()int a,b,c,d,e;for(a=1;a=100;a+)for(b=1;b=100;b+)for(c=1;c=100;c+)if(a+b+c=100)&(9*a+6*b+c=300)printf(母鸡%d只,公鸡%d只,小鸡%d只。n,a,b,c);4.#includevoid main()char i,j,k;for(i=X;i=Z;i+)for(j=X;j=Z;j+)for(k=X;k=Z;k+)if(i!=j&i!=k&j!=k)if(i!=X&k!=X&k!=Z)printf(A
12、-%ctB-%ctC-%cn,i,j,k);实验五1.#includevoid main()int a11=1,4,6,9,13,16,19,28,40,100;int t1,t2,n,e,i,j;printf(原有数组为:n);for(i=0;ie)a10=n;elsefor(i=0;in)t1=ai;ai=n;for(j=i+1;j11;j+)t2=aj;aj=t1;t1=t2;break;for(i=0;i11;i+)printf(%d ,ai);printf(n);2.#includevoid main()int a10,i,j,t;printf(请输入十个整数:);for(i=0;i
13、10;i+)scanf(%d,&ai);for(i=0,j=10;ij;i+,j-)t=ai;ai=aj;aj=t;printf(逆序存放后的数组为:);for(i=0;i10;i+)printf(%d ,ai);printf(n);3.#includevoid main()int x,mid,top,bottom,a15=1,2,3,4,5,6,7,8,11,14,35,68,70,87,99;printf(请输入要查找的数:);scanf(%d,&x);bottom=0;top=14;while(bottom=top)mid=(top+bottom)/2;if(xamid)bottom=m
14、id+1;else break;if(bottom=top)printf(%d在数组中的下标为%dn,x,mid);else printf(查无此数!n);4.#include#includevoid main()char a80;int i;printf(请输入一个字符串:n);gets(a);for(i=0;istrlen(a);i+)if(a=ai&ai=z)ai=ai-32;else if(A=ai&ai=Z)ai=ai+32;puts(a);5.#includevoid main()long a,b;int i;a=b=1;printf(斐波那契数列的前20项分别为:n);print
15、f(%7ld%7ld,a,b);for(i=3;i=20;i+)a=a+b;printf(%7ld,a); if(i%5=0)printf(n);i+;b=a+b;printf(%7ld,b);if(i%5=0)printf(n);实验六1.#define M 5#define N 5#includevoid main()int i,j;char aMN;for(i=0;i5;i+) for(j=0;j5;j+)aij=*;printf(%c,aij);printf(n);2.#includevoid main()int i,j,a1010;printf(n);for(i=0;i10;i+)a
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