金融时间序列分析报告报告材料第一次作业.doc
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1、worda. 用百分数表示简单月收益率略表1.三支股票的简单日收益率百分比的描述性统计American ExpressCaterpillarStarbucksMean0.09718%0.08473%0.145%Standard Deviation2.250181%2.153127%3.049927%SkewnessExcess KurtosisMinimum Value-13.596%-12.162%-28.286%Maximum Value12.770%10.845%14.706%b.简单收益率换成对数收益率略c.把对数收益率用百分比表示出来略表2.三支股票的对数日收益率百分比的描述性统计A
2、merican ExpressCaterpillarStarbucksMean0.07188%0.06157%0.09839%Standard Deviation2.248449%2.150728%3.055389%SkewnessExcess KurtosisMinimum Value-14.61362%-12.96760%-33.24842%Maximum Value12.01802%10.29626%13.72021%d. 对数收益率零均值检验=0.051对于American Expressdata: dailylogre$V2 alternative hypothesis: true
3、mean is not equal to 0 95 percent confidence interval: -0.01596993 0.15972365 sample estimates: mean of x 故承受原假设2对于Caterpillardata: dailylogre$V3 alternative hypothesis: true mean is not equal to 0 95 percent confidence interval: -0.02245558 0.14560208 sample estimates: mean of x 故承受原假设3对于Starbucksd
4、ata: dailylogre$V4 alternative hypothesis: true mean is not equal to 0 95 percent confidence interval:-0.02098409 0.21776370 sample estimates: mean of x 故承受原假设a. 用百分数表示简单月收益率略表1.四支股票的简单月收益率百分比的描述性统计IBMVWEWSPMean1.175%1.191%1.591%0.9032%Std. Dev.7.813905%4.561798%5.653741%4.443510%SkewnessExcess Kurt
5、osisMin. Value-26.190%-22.534%-27.231%-21.763%Max. Value35.380%14.150%29.921%13.177%b.简单收益率换成对数收益率略c.把对数收益率用百分比表示出来略表2.四支股票的对数月收益率百分比的描述性统计IBMVWEWSPMean0.8722%1.080%1.421%0.8006%Std. Dev.7.713084%4.594938%5.652219%4.469454%SkewnessExcess KurtosisMin. Value-30.3676%-25.533%-31.788%-24.5428%Max. Value
6、30.2915%13.234%26.176%12.3783%d. 对数收益率零均值检验=0.051对于IBMdata: dailylogre$V2 alternative hypothesis: true mean is not equal to 0 95 percent confidence interval: 0.05899196 1.68541655 sample estimates:mean of x 故拒绝原假设2对于VWdata: dailylogre$V3 alternative hypothesis: true mean is not equal to 0 95 percent
7、 confidence interval: 0.5955359 1.5644506 sample estimates:mean of x 故拒绝原假设3对于EWdata: dailylogre$V4 alternative hypothesis: true mean is not equal to 0 95 percent confidence interval: 0.8250521 2.0169110 sample estimates:mean of x 故拒绝原假设4对于SPdata: dailylogre$V5 alternative hypothesis: true mean is n
8、ot equal to 0 95 percent confidence interval: 0.329396 1.271850 sample estimates:mean of x 故拒绝原假设a. 平均年对数收益率=t=19752004Rt2004-1975=t=19752005i=112rti29其中,Rt为第t年对数收益率,rti为第t年第i月的月对数收益率如此SP的平均年对数收益率=9.607479%b. A=Cert=1e0.09607479(2004-1975)=16.21876a.H0:Sraxp=0,=0.05建立检验统计量t=S(r)6TN(0,1)计算结果为t=1.8110
9、6p=0.070132Accept Null Hypothesis故承受原假设b. H0:Kraxp=0,=0.05建立检验统计量t=Kr-324TN(0,1)计算结果为t=-6.23215p=4.60076e-10Reject Null Hypthesis;Accept Alternative Hypothesis故拒绝原假设,承受被择假设a.计算月对数收益率略b. 表3汇率的对数收益率的描述性统计CAUKJPEUMeanStd. Dev.SkewnessExcess KurtosisMin. ValueMax. Valuec. 汇率对数收益率的经验特征Appendixsetwd(F:/Fi
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