临时用电施工组织少现场配电布置图.doc

目 录一、编制依据 .2二、工程简况 .2三、配电箱布置及线路走向.3四、施工现场用电量统计表.3五、设计内容和步骤.3-37六、绘制临时供电施工图.37-49七、临时用电设施安装.49-50八、安全用电技术措施及电气防火措施.50-51九、触电事故应急救援预案.52-55十、安全生产保证体系.56十一、附图一、编制依据低压配电设计规范GB50054-95中国建筑工业出版社建筑工程施工现场供电安全规范GB50194-93中国建筑工业出版社通用用电设备配电设计规范GB50055-93中国建筑工业出版社供配电系统设计规范GB50052-95中国建筑工业出版社施工现场临时用电安全技术规范JGJ46-2005中国建筑工业出版社建筑施工安全检查标准JGJ59-99二、工程简况工程名称：秦皇岛中农物流储备工程工程建设地点：该工程位于秦皇岛市北环路以北,八三专用线以东,本工程由四个单体组成.建设规模：综合服务楼：结构类型为3层钢筋混凝土结构,建筑高度11.7m,建筑面积3060 m2；建筑物长65.30M,宽16.50M,6-7轴之间设一道抗震缝,基础为独立基础.设计使用年限为50年.耐火等级二级；抗震设防烈度为7度.一号库房：结构类型为单层轻钢结构,建筑高度7.05m,建筑面积1621.27m2,建筑物长度为45.50M,宽度为42.50M,最大单跨21M.建筑功能为仓库,所储存物品火灾危险性分类为戊类.设计使用年限为50年,耐火等级为二级,屋面防水等级为二级,抗震设防烈度为7度.二号库房：结构类型为单层轻钢结构,建筑高度7.05m,建筑面积11940.70m2,建筑物长度为122.90M,宽度为126.50M,最大单跨21M.建筑功能为仓库,所储存物品火灾危险性分类为戊类.设计使用年限为50年,耐火等级为二级,屋面防水等级为二级,抗震设防烈度为7度.三号库房：结构类型为单层轻钢结构,建筑高度7.05m,建筑面积5611.45 m2,建筑物长度为115.7M,宽度为48.50M,最大单跨24M.建筑功能为仓库,所储存物品火灾危险性分类为戊类.设计使用年限为50年,耐火等级为二级,屋面防水等级为二级,抗震设防烈度为7度.三、配电箱布置及线路走向施工用电由建设单位提供地现场总配电箱接入,由总电源箱内600A塑壳断路器引至现场总配电柜,在由总电柜分出8路,在分别到木工加工区配电箱、钢筋加工区配电箱、焊工棚配电箱、搅拌机配电箱、综合服务楼配电箱及一、二、三号库房配电箱具体布置及走向见平面图.四、 施工现场用电量统计表:-序号机具名称型号安装功率(kW) 数量合计功率(kW)1 插入式振动器 ZX50C 1.1 55.52 平板式振动器 ZB11 1.1 1 1.1 3自落式混凝土搅拌机 JD250 11 1 11 4钢筋调直机 GT4/14 4 1 4 5钢筋切断机 QJ40-1 5.5 2116套丝机 GT3/9 7.5 2157钢筋弯曲机 GW40 3 268木工电刨 MIB2-80/1 0.7 1 0.7 9木工圆锯 MJ104 3 1 3 10交流电焊机 BX3-200-2 23.4 246.811直流电焊机 AX-320(AT-320) 14 1021012 40塔吊 1-五、 设计内容和步骤1、现场勘探及初步设计:(1)本工程所在施工现场范围内施工前无各种埋地管线.(2)现场采用380V低压供电,设一配电总箱,内有计量设备,采用TN-S系统供电.(3)根据施工现场用电设备布置情况,总箱进线采用导线直接埋地敷设,干线采用直接埋地敷设,用电器导线采用直接埋地敷设.布置位置及线路走向参见临时配电系统图及现场平面图,采用三级配电,三级防护.(4)按照JGJ46-2005规定制定施工组织设计,接地电阻R4.2、确定用电负荷:(1)、插入式振动器Kx = 0.3 Cos = 0.7 tg = 1.02Pjs = 0.3×1.1 = 0.33 kWQjs = Pjs× tg=0.33×1.02 = 0.34 kvar(2)、平板式振动器Kx = 0.3 Cos = 0.7 tg = 1.02Pjs = 0.3×1.1 = 0.33 kWQjs = Pjs× tg=0.33×1.02 = 0.34 kvar(3)、插入式振动器Kx = 0.3 Cos = 0.7 tg = 1.02Pjs = 0.3×1.1 = 0.33 kWQjs = Pjs× tg=0.33×1.02 = 0.34 kvar(4)、插入式振动器Kx = 0.3 Cos = 0.7 tg = 1.02Pjs = 0.3×1.1 = 0.33 kWQjs = Pjs× tg=0.33×1.02 = 0.34 kvar(5)、插入式振动器Kx = 0.3 Cos = 0.7 tg = 1.02Pjs = 0.3×1.1 = 0.33 kWQjs = Pjs× tg=0.33×1.02 = 0.34 kvar(6)、插入式振动器Kx = 0.3 Cos = 0.7 tg = 1.02Pjs = 0.3×1.1 = 0.33 kWQjs = Pjs× tg=0.33×1.02 = 0.34 kvar(7)、自落式混凝土搅拌机Kx = 0.75 Cos = 0.85 tg = 0.62Pjs = 0.75×11 = 8.25 kWQjs = Pjs× tg=8.25×0.62 = 5.11 kvar(8)、钢筋调直机Kx = 0.65 Cos = 0.7 tg = 1.02Pjs = 0.65×4 = 2.6 kWQjs = Pjs× tg=2.6×1.02 = 2.65 kvar(9)、钢筋切断机Kx = 0.65 Cos = 0.7 tg = 1.02Pjs = 0.65×5.5 = 3.575 kWQjs = Pjs× tg=3.58×1.02 = 3.65 kvar(10)、套丝机Kx = 0.65 Cos = 0.7 tg = 1.02Pjs = 0.65×7.5 = 4.875 kWQjs = Pjs× tg=4.88×1.02 = 4.97 kvar(11)、钢筋切断机Kx = 0.65 Cos = 0.7 tg = 1.02Pjs = 0.65×5.5 = 3.575 kWQjs = Pjs× tg=3.58×1.02 = 3.65 kvar(12)、套丝机Kx = 0.65 Cos = 0.7 tg = 1.02Pjs = 0.65×7.5 = 4.875 kWQjs = Pjs× tg=4.88×1.02 = 4.97 kvar(13)、钢筋弯曲机Kx = 0.65 Cos = 0.7 tg = 1.02Pjs = 0.65×3 = 1.95 kWQjs = Pjs× tg=1.95×1.02 = 1.99 kvar(14)、钢筋弯曲机Kx = 0.65 Cos = 0.7 tg = 1.02Pjs = 0.65×3 = 1.95 kWQjs = Pjs× tg=1.95×1.02 = 1.99 kvar(15)、木工电刨Kx = 0.65 Cos = 0.6 tg = 1.33Pjs = 0.65×0.7 = 0.455 kWQjs = Pjs× tg=0.45×1.33 = 0.61 kvar(16)、木工圆锯Kx = 0.65 Cos = 0.6 tg = 1.33Pjs = 0.65×3 = 1.95 kWQjs = Pjs× tg=1.95×1.33 = 2.6 kvar(17)、交流电焊机Kx = 0.5 Cos = 0.4 tg = 2.29将Jc =50%统一换算到Jc1 =100%地额定容量Pn = Sn×Cos = 23.4×0.4=9.36kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.5/1)1/2×9.36 = 6.62 kWPjs = Kx×Pe =0.5×6.62 = 3.31kWQjs = Pjs× tg=3.31×2.29 = 7.58 kvar(18)、交流电焊机Kx = 0.5 Cos = 0.4 tg = 2.29将Jc =50%统一换算到Jc1 =100%地额定容量Pn = Sn×Cos = 23.4×0.4=9.36kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.5/1)1/2×9.36 = 6.62 kWPjs = Kx×Pe =0.5×6.62 = 3.31kWQjs = Pjs× tg=3.31×2.29 = 7.58 kvar(19)、直流电焊机Kx = 0.7 Cos = 0.6 tg = 1.33将Jc =50%统一换算到Jc1 =100%地额定容量Pn = 14kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.5/1)1/2×14 = 9.9 kWPjs = Kx×Pe =0.7×9.9 = 6.93kWQjs = Pjs× tg=6.93×1.33 = 9.24 kvar(20)、直流电焊机Kx = 0.7 Cos = 0.6 tg = 1.33将Jc =50%统一换算到Jc1 =100%地额定容量Pn = 14kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.5/1)1/2×14 = 9.9 kWPjs = Kx×Pe =0.7×9.9 = 6.93kWQjs = Pjs× tg=6.93×1.33 = 9.24 kvar(21)、直流电焊机Kx = 0.7 Cos = 0.6 tg = 1.33将Jc =50%统一换算到Jc1 =100%地额定容量Pn = 14kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.5/1)1/2×14 = 9.9 kWPjs = Kx×Pe =0.7×9.9 = 6.93kWQjs = Pjs× tg=6.93×1.33 = 9.24 kvar(22)、直流电焊机Kx = 0.7 Cos = 0.6 tg = 1.33将Jc =50%统一换算到Jc1 =100%地额定容量Pn = 14kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.5/1)1/2×14 = 9.9 kWPjs = Kx×Pe =0.7×9.9 = 6.93kWQjs = Pjs× tg=6.93×1.33 = 9.24 kvar(23)、直流电焊机Kx = 0.7 Cos = 0.6 tg = 1.33将Jc =50%统一换算到Jc1 =100%地额定容量Pn = 14kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.5/1)1/2×14 = 9.9 kWPjs = Kx×Pe =0.7×9.9 = 6.93kWQjs = Pjs× tg=6.93×1.33 = 9.24 kvar(24)、直流电焊机Kx = 0.7 Cos = 0.6 tg = 1.33将Jc =50%统一换算到Jc1 =100%地额定容量Pn = 14kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.5/1)1/2×14 = 9.9 kWPjs = Kx×Pe =0.7×9.9 = 6.93kWQjs = Pjs× tg=6.93×1.33 = 9.24 kvar(25)、直流电焊机Kx = 0.7 Cos = 0.6 tg = 1.33将Jc =50%统一换算到Jc1 =100%地额定容量Pn = 14kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.5/1)1/2×14 = 9.9 kWPjs = Kx×Pe =0.7×9.9 = 6.93kWQjs = Pjs× tg=6.93×1.33 = 9.24 kvar(26)、直流电焊机Kx = 0.7 Cos = 0.6 tg = 1.33将Jc =50%统一换算到Jc1 =100%地额定容量Pn = 14kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.5/1)1/2×14 = 9.9 kWPjs = Kx×Pe =0.7×9.9 = 6.93kWQjs = Pjs× tg=6.93×1.33 = 9.24 kvar(27)、直流电焊机Kx = 0.7 Cos = 0.6 tg = 1.33将Jc =50%统一换算到Jc1 =100%地额定容量Pn = 14kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.5/1)1/2×14 = 9.9 kWPjs = Kx×Pe =0.7×9.9 = 6.93kWQjs = Pjs× tg=6.93×1.33 = 9.24 kvar(28)、直流电焊机Kx = 0.7 Cos = 0.6 tg = 1.33将Jc =50%统一换算到Jc1 =100%地额定容量Pn = 14kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.5/1)1/2×14 = 9.9 kWPjs = Kx×Pe =0.7×9.9 = 6.93kWQjs = Pjs× tg=6.93×1.33 = 9.24 kvar(29)、直流电焊机Kx = 0.7 Cos = 0.6 tg = 1.33将Jc =50%统一换算到Jc1 =100%地额定容量Pn = 14kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.5/1)1/2×14 = 9.9 kWPjs = Kx×Pe =0.7×9.9 = 6.93kWQjs = Pjs× tg=6.93×1.33 = 9.24 kvar(30)、直流电焊机Kx = 0.7 Cos = 0.6 tg = 1.33将Jc =50%统一换算到Jc1 =100%地额定容量Pn = 14kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.5/1)1/2×14 = 9.9 kWPjs = Kx×Pe =0.7×9.9 = 6.93kWQjs = Pjs× tg=6.93×1.33 = 9.24 kvar(31)、直流电焊机Kx = 0.7 Cos = 0.6 tg = 1.33将Jc =50%统一换算到Jc1 =100%地额定容量Pn = 14kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.5/1)1/2×14 = 9.9 kWPjs = Kx×Pe =0.7×9.9 = 6.93kWQjs = Pjs× tg=6.93×1.33 = 9.24 kvar(32)、直流电焊机Kx = 0.7 Cos = 0.6 tg = 1.33将Jc =50%统一换算到Jc1 =100%地额定容量Pn = 14kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.5/1)1/2×14 = 9.9 kWPjs = Kx×Pe =0.7×9.9 = 6.93kWQjs = Pjs× tg=6.93×1.33 = 9.24 kvar(33)、直流电焊机Kx = 0.7 Cos = 0.6 tg = 1.33将Jc =50%统一换算到Jc1 =100%地额定容量Pn = 14kWPe = n×(Jc/Jc1)1/2×Pn = 1×(0.5/1)1/2×14 = 9.9 kWPjs = Kx×Pe =0.7×9.9 = 6.93kWQjs = Pjs× tg=6.93×1.33 = 9.24 kvar(34)总地计算负荷计算,总箱同期系数取 Kx = 0.9总地有功功率Pjs = Kx×Pjs = 0.9×(0.33+0.33+0.33+0.33+0.33+0.33+8.25+2.6+3.58+4.88+3.58+4.88+1.95+1.95+0.45+1.95+3.31+3.31+6.93+6.93+6.93+6.93+6.93+6.93+6.93+6.93+6.93+6.93+6.93+6.93+6.93+6.93+6.93) = 131.938 kW总地无功功率Qjs = Kx×Qjs =0.9×(0.34+0.34+0.34+0.34+0.34+0.34+5.11+2.65+3.65+4.97+3.65+4.97+1.99+1.99+0.61+2.6+7.58+7.58+9.24+9.24+9.24+9.24+9.24+9.24+9.24+9.24+9.24+9.24+9.24+9.24+9.24+9.24+9.24) = 169.175 kvar总地视在功率Sjs = ( Pjs2+Qjs2 )1/2 = (131.9382+169.1752)1/2 = 214.541 kVA总地计算电流计算Ijs = Sjs/(1.732×Ue) = 214.541/(1.732×0.38) = 325.971 A3、1号干线线路上导线截面及分配箱、开关箱内电气设备选择:在选择前应对照平面图和系统图先由用电设备至开关箱计算,再由开关箱至分配箱计算,选择导线及开关设备.分配箱至开关箱,开关箱至用电设备地导线敷设采用铜橡皮绝缘导线.(1)、插入式振动器开关箱至插入式振动器导线截面及开关箱内电气设备选择（开关箱以下用电器启动后需要系数取1）:i)计算电流Kx = 1 Cos = 0.7 tg = 1.02Ijs = Kx×Pe /(1.732×Ue×Cos) = 1×1.1/(1.732×0.38×0.7) = 2.39Aii)选择导线选择XV-4×10 ,直接埋地时其安全载流量为71A.iii)选择电气设备选择开关箱内隔离开关为DZ5-20/3 ,其脱扣器整定电流值为Ir = 16A,漏电保护器为 DZ15L-100/30.(2)、平板式振动器开关箱至平板式振动器导线截面及开关箱内电气设备选择（开关箱以下用电器启动后需要系数取1）:i)计算电流Kx = 1 Cos = 0.7 tg = 1.02Ijs = Kx×Pe /(1.732×Ue×Cos) = 1×1.1/(1.732×0.38×0.7) = 2.39Aii)选择导线选择XV-4×10 ,直接埋地时其安全载流量为71A.iii)选择电气设备选择开关箱内隔离开关为DZ5-20/3 ,其脱扣器整定电流值为Ir = 16A,漏电保护器为 DZ15L-100/30.(3)、插入式振动器开关箱至插入式振动器导线截面及开关箱内电气设备选择（开关箱以下用电器启动后需要系数取1）:i)计算电流Kx = 1 Cos = 0.7 tg = 1.02Ijs = Kx×Pe /(1.732×Ue×Cos) = 1×1.1/(1.732×0.38×0.7) = 2.39Aii)选择导线选择XV-4×10 ,直接埋地时其安全载流量为71A.iii)选择电气设备选择开关箱内隔离开关为DZ5-20/3 ,其脱扣器整定电流值为Ir = 16A,漏电保护器为 DZ15L-100/30.(4)、插入式振动器开关箱至插入式振动器导线截面及开关箱内电气设备选择（开关箱以下用电器启动后需要系数取1）:i)计算电流Kx = 1 Cos = 0.7 tg = 1.02Ijs = Kx×Pe /(1.732×Ue×Cos) = 1×1.1/(1.732×0.38×0.7) = 2.39Aii)选择导线选择XV-4×10 ,直接埋地时其安全载流量为71A.iii)选择电气设备选择开关箱内隔离开关为DZ5-20/3 ,其脱扣器整定电流值为Ir = 16A,漏电保护器为 DZ15L-100/30.(5)、插入式振动器开关箱至插入式振动器导线截面及开关箱内电气设备选择（开关箱以下用电器启动后需要系数取1）:i)计算电流Kx = 1 Cos = 0.7 tg = 1.02Ijs = Kx×Pe /(1.732×Ue×Cos) = 1×1.1/(1.732×0.38×0.7) = 2.39Aii)选择导线选择XV-4×10 ,直接埋地时其安全载流量为71A.iii)选择电气设备选择开关箱内隔离开关为DZ5-20/3 ,其脱扣器整定电流值为Ir = 16A,漏电保护器为 DZ15L-100/30.(6)、插入式振动器开关箱至插入式振动器导线截面及开关箱内电气设备选择（开关箱以下用电器启动后需要系数取1）:i)计算电流Kx = 1 Cos = 0.7 tg = 1.02Ijs = Kx×Pe /(1.732×Ue×Cos) = 1×1.1/(1.732×0.38×0.7) = 2.39Aii)选择导线选择XV-4×10 ,直接埋地时其安全载流量为71A.iii)选择电气设备选择开关箱内隔离开关为DZ5-50/3 ,其脱扣器整定电流值为Ir = 40A,漏电保护器为 DZ15L-100/30.(7)、1号动力分箱至第1组电机(插入式振动器、平板式振动器、插入式振动器、插入式振动器、插入式振动器、插入式振动器)地开关箱地导线截面及分配箱内开关地选择i) 计算电流插入式振动器Kx = 0.3 Cos= 0.7 tg= 1.02Ijs= Kx ×Pe ×台数/(1.732×Ue ×Cos) = 0.3×1.1×1/(1.732×0.38×0.7) = 0.72A平板式振动器Kx = 0.3 Cos= 0.7 tg= 1.02Ijs= Kx ×Pe ×台数/(1.732×Ue ×Cos) = 0.3×1.1×1/(1.732×0.38×0.7) = 0.72A插入式振动器Kx = 0.3 Cos= 0.7 tg= 1.02Ijs= Kx ×Pe ×台数/(1.732×Ue ×Cos) = 0.3×1.1×1/(1.732×0.38×0.7) = 0.72A插入式振动器Kx = 0.3 Cos= 0.7 tg= 1.02Ijs= Kx ×Pe×台数/(1.732×Ue ×Cos) = 0.3×1.1×1/(1.732×0.38×0.7) = 0.72A插入式振动器Kx = 0.3 Cos= 0.7 tg= 1.02Ijs= Kx ×Pe ×台数/(1.732×Ue ×Cos) = 0.3×1.1×1/(1.732×0.38×0.7) = 0.72A插入式振动器Kx = 0.3 Cos= 0.7 tg= 1.02Ijs= Kx ×Pe ×台数/(1.732×Ue ×Cos) = 0.3×1.1×1/(1.732×0.38×0.7) = 0.72AIjs(1组电机 )= 4.3A该组中最大地开关箱电流Ijs=2.39A由于该组下有多个开关箱,所以最大电流需要乘以1.1地系数两者中取大值Ijs=4.30×1.1=4.73Aii)选择导线选择XV-4×10 ,直接埋地时其安全载流量为71A.iii)选择电气设备选择分配箱内开关为DZ5-50/3 ,其脱扣器整定电流值为Ir = 40A,漏电保护器为 DZ15L-100/30.(8)1号动力分箱进线及进线开关地选择i)计算电流Kx = 0.7,Cos = 0.9Ijs = Kx×Pe /(1.732×Ue×Cos) = 0.7×6.6/(1.732×0.38×0.9) = 7.8A该分箱下最大组线电流Ijs=4.73A两者中取大值Ijs=7.80Aii)选择导线选择XV-4×10 ,直接埋地时其安全载流量为71A.iii)选择电气设备选择分配箱内开关为DZ5-50/3 ,其脱扣器整定电流值为Ir = 40A,漏电保护器为 DZ15L-100/30.(9)1号干线导线截面及出线开关地选择i) 计算电流：按导线安全载流量：Kx = 0.7 ,Cos = 0.9Ijs = Kx×Pe/(1.732×Ue×Cos) = 0.7×6.6/(1.732×0.38×0.9) = 7.8 A该干线下最大地分配箱电流Ijs=7.80A选择地电流Ijs=7.80A按允许电压降：S = Kx×(P×L)/CU = 0.7×330/(77×5) = 0.6 mm2选择XV-4×10 ,直接埋地时其安全载流量为71A.ii)选择出线开关1号干线出线开关选择DZ5-50/3 ,其脱扣器整定电流值为Ir = 40A,漏电保护器为 DZ15L-100/30.4、2号干线线路上导线截面及分配箱、开关箱内电气设备选择:在选择前应对照平面图和系统图先由用电设备至开关箱计算,再由开关箱至分配箱计算,选择导线及开关设备.分配箱至开关箱,开关箱至用电设备地导线敷设采用铜橡皮绝缘导线,漏电保护器为 DZ15L-100/30.(1)、自落式混凝土搅拌机开关箱至自落式混凝土搅拌机导线截面及开关箱内电气设备选择（开关箱以下用电器启动后需要系数取1）:i)计算电流Kx = 1 Cos = 0.85 tg = 0.62Ijs = Kx×Pe /(1.732×Ue×Cos) = 1×11/(1.732×0.38×0.85) = 19.66Aii)选择导线选择XV-4×10 ,直接埋地时其安全载流量为71A.iii)选择电气设备选择开关箱内隔离开关为DZ5-50/3 ,其脱扣器整定电流值为Ir = 40A,漏电保护器为 DZ15L-100/30.(2)、2号动力分箱至第1组电机(自落式混凝土搅拌机)地开关箱地导线截面及分配箱内开关地选择i) 计算电流自落式混凝土搅拌机Kx = 0.75 Cos= 0.85 tg= 0.62Ijs= Kx ×Pe ×台数/(1.732×Ue ×Cos) = 0.75×11×1/(1.732×0.38×0.85) = 14.75AIjs(1组电机 )= 14.75A该组中最大地开关箱电流Ijs=19.66A两者中取大值Ijs=19.66Aii)选择导线选择XV-4×10 ,直接埋地时其安全载流量为71A.iii)选择电气设备选择分配箱内开关为DZ5-50/3 ,其脱扣器整定电流值为Ir = 40A,漏电保护器为 DZ15L-100/30.(3)2号动力分箱进线及进线开关地选择i)计算电流Kx = 0.7,Cos = 0.9Ijs = Kx×Pe /(1.732×Ue×Cos) = 0.7×11/(1.732×0.38×0.9) = 13A该分箱下最大组线电流Ijs=19.66A两者中取大值Ijs=19.66Aii)选择导线选择XV-4×10 ,直接埋地时其安全载流量为71A.iii)选择电气设备选择分配箱内开关为DZ5-50/3 ,其脱扣器整定电流值为Ir = 40A,漏电保护器为 DZ15L-100/30.(4)2号干线导线截面及出线开关地选择i) 计算电流：按导线安全载流量：Kx = 0.7 ,Cos = 0.9Ijs = Kx×Pe/(1.732×Ue×Cos) = 0.7×11/(1.732×0.38×0.9) = 13 A该干线下最大地分配箱电流Ijs=19.66A选择地电流Ijs=19.66A按允许电压降：S = Kx×(P×L)/CU = 0.7×880/(77×5) = 1.6 mm2选择XV-4×10 ,直接埋地时其安全载流量为71A.ii)选择出线开关2号干线出线开关选择DZ5-50/3 ,其脱扣器整定电流值为Ir = 40A,漏电保护器为 DZ15L-100/30.5、3号干线线路上导线截面及分配箱、开关箱内电气设备选择:在选择前应对照平面图和系统图先由用电设备至开关箱计算,再由开关箱至分配箱计算,选择导线及开关设备.分配箱至开关箱,开关箱至用电设备地导线敷设采用铜橡皮绝缘导线,漏电保护器为 DZ15L-100/30.(1)、钢筋调直机开关箱至钢筋调直机导线截面及开关箱内电气设备选择（开关箱以下用电器启动后需要系数取1）:i)计算电流Kx = 1 Cos = 0.7 tg = 1.02Ijs = Kx×Pe /(1.732×Ue×Cos) = 1×4/(1.732×0.38×0.7) = 8.68Aii)选择导线选择XV-4×16 ,直接埋地时其安全载流量为93A.iii)选择电气设备选择开关箱内隔离开关为Hk1-15/3,漏电保护器为 DZ15L-100/30.(2)、钢筋切断机开关箱至钢筋切断机导线截面及开关箱内电气设备选择（开关箱以下用电器启动后需要系数取1）:i)计算电流Kx = 1 Cos = 0.7 tg = 1.02Ijs = Kx×Pe /(1.732×Ue×Cos) = 1×5.5/(1.732×0.38×0.7) = 11.94Aii)选择导线选择XV-4×16 ,直接埋地时其安全载流量为93A.iii)选择电气设备选择开关箱内隔离开关为Hk1-30/3,漏电保护器为 DZ15L-100/30.(3)、套丝机开关箱至套丝机导线截面及开关箱内电气设备选择（开关箱以下用电器启动后需要系数取1）:i)计算电流Kx = 1 Cos = 0.7 tg = 1.02Ijs = Kx×Pe /(1.732×Ue×Cos) = 1×7.5/(1.732×0.38×0.7) = 16.28Aii)选择导线选择XV-4×16 ,直接埋地时其安全载流量为93A.iii)选择电气设备选择开关箱内隔离开关为DZ5-50/3 ,其脱扣器整定电流值为Ir = 40A,漏电保护器为 DZ15L-100/30.(4)、钢筋切断机开关箱至钢筋切断机导线截面及开关箱内电气设备选择（开关箱以下用电器启动后需要系数取1）:i)计算电流Kx = 1 Cos = 0.7 tg = 1.02Ijs = Kx×Pe /(1.732×Ue×Cos) = 1×5.5/(1.732×0.38×0.7) = 11.94Aii)选择导线选择XV-4×10 ,直接埋地时其安全载流量为71A.iii)选择电气设备选择开关箱内隔离开关为Hk1-15/3,漏电保护器为 DZ15L-100/30.(5)、套丝机开关箱至套丝机导线截面及开关箱内电气设备选择（开关箱以下用电器启动后需要系数取1）:i)计算电流Kx = 1 Cos = 0.7 tg = 1.02Ijs = Kx×Pe /(1.732×Ue×Cos) = 1×7.5/(1.732×0.38×0.7) = 16.28Aii)选择导线选择XV-4×16 ,直接埋地时其安全载流量为93A.iii)选择电气设备选择开关箱内隔离开关为DZ10-100/3 ,其脱扣器整定电流值为Ir = 80A,漏电保护器为 DZ15L-100/30.(6)、钢筋弯曲机开关箱至钢筋弯曲机导线截面及开关箱内电气设备选择（开关箱以下用电器启动后需要系数取1）:i)计算电流Kx = 1 Cos = 0.7 tg = 1.02Ijs = Kx×Pe /(1.732×Ue×Cos) = 1×3/(1.732×0.38×0.7) = 6.51Aii)选择导线选择XV-4×16 ,直接埋地时其安全载流量为93A.iii)选择电气设备选择开关箱内隔离开关为Hk1-15/3,漏电保护器为 DZ15L-100/30.(7)、钢筋弯曲机开关箱至钢筋弯曲机导线截面及开关箱内电气设备选择（开关箱以下用电器启动后需要系数取1）:i)计算电流Kx = 1 Cos = 0.7 tg = 1.02Ijs = Kx×Pe /(1.732×Ue×Cos) = 1×3/